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Zaina Siddiqi
Zaina Siddiqi
Welcome to another SAT Math guide! The Passport to Advanced Math portion of the SAT Math exam makes up 16/58 questions, or about 28% of the math section. After mastering this section, you'll be able to analyze more complex equations and solve systems! Let's get started. 🎈
➗ Operations with Polynomials and Rewriting Expressions
Let's begin with operations, which is all about adding, subtracting, and multiplying polynomials.
Skill group number two is all about building quadratic functions! Now let's get into what a quadratic is. 👟
Let's say we have the quadratic expression 3x² - 7x + 2 and we are tasked with finding the solutions (roots) to its corresponding quadratic equation.
Onto group three of skills in this topic! Let's discuss a few vocabulary terms you should be familiar with.
Rational equations often feel tough at first, but once you get in the grove, it gets easier! 🕺🏻🪩
Solve for x in the equation (x + 3)/(2x) = 1/(x - 2).
🤔 Step 1: Identify the domain The expressions have denominators of 2x and (x - 2). To find the domain, set each denominator equal to zero and solve for x:
✖️ Step 2: Cross-multiplication
Multiply the numerator of the first fraction with the denominator of the second fraction, and vice versa: (x + 3)(x - 2) = 2x.
👩🏽💻 Step 3: Simplifying
Expand the left side by distributing: x² - 2x + 3x - 6 = 2x.
Combine like terms: x² + x - 6 = 2x.
💘 Step 4: Solving for the variable
Move all terms to one side to set the equation to zero: x² + x - 2x - 6 = 0.
Simplify further: x² - x - 6 = 0.
🥳 Step 5: Factor the quadratic equation (if possible)
In this case, the equation can be factored as: (x - 3)(x + 2) = 0.
✅ Step 6: Solve for x
Now, use the zero product property, which states that if the product of two factors is zero, then at least one of the factors must be zero:
Since we identified earlier that x cannot be 0 or 2, we need to check the solutions we obtained (x = 3 and x = -2) to ensure they are valid within the domain.
The final solution is x = 3, as x = -2 would make the denominator (x - 2) zero.
Therefore, the solution to the rational equation is x = 3. Phew, that was a lot.
Let's take a simple system of equations with two variables, x and y:
Equation 1: 2x + y = 8
Equation 2: x - y = 2
In this system, we have two equations involving the variables x and y. Our goal is to find the values of x and y that satisfy both equations simultaneously.
Now, let's go through this step by step.
Algebraic Representation: The function is given as f(x) = 2x + 1. This means that for any input value "x," the output "f(x)" is equal to twice the value of "x" plus one. For instance, if we plug in "x = 3," the algebraic representation gives us:
Graphical Representation: To graph this function, we'll plot points on the coordinate plane. Choose several "x" values, find their corresponding "f(x)" values using the algebraic representation, and plot the points (x, f(x)).
Visually, you can see that as the "x" values increase, the "y" values increase twice as fast (due to the coefficient 2) and are always one unit higher (due to the constant term 1). This relationship is evident in both the algebraic and graphical representations. Changes in "x" directly impact the corresponding "y" values, and this connection between the two representations helps us better understand the behavior of functions.
Function notation is a way of representing mathematical relationships between variables. It uses specific symbols to show how one quantity (usually called the input) is related to another quantity (usually called the output). Key concepts in function notation are:
A function notation typically looks like this: f(x). Here, "f" is the name of the function, and "x" represents the input variable. The output of the function when the input is "x" is denoted as f(x).
Now, let's look at an example and explain it step by step: Let's define a function "f" that takes an input "x" and returns the value of 2 times "x" plus 3.
Let's consider a simple example of a function and its graph:
Function: The function represents the relationship between the cost (C) of buying a certain number of tickets (n) to a movie. Let's assume the cost of each ticket is $10.
Equation: The equation for this situation is C = 10 * n. Here, 'n' is the number of tickets purchased, and 'C' is the total cost.
Graph: Now, let's plot the graph of this function. We'll use the x-axis to represent the number of tickets (n) and the y-axis to represent the cost (C).
Graphically, you can see that as the number of tickets increases (n), the cost (C) also increases linearly. Each point on the graph represents a specific input-output pair. For example, if you purchase 2 tickets (n = 2), the total cost would be $20 (C = 10 * 2).
Suppose you want to find out how many tickets you can buy with $50. To do this, we rearrange the equation to solve for 'n': C = 10 * n
Divide both sides by 10: C / 10 = n
Now, plug in C = 50: n = 50 / 10
n = 5
So, you can buy 5 tickets with $50.
This example illustrates how to find connections between the function, its graph, and the situation it represents. It also demonstrates how to rearrange the equation to find the value of interest (number of tickets) given a specific cost.
Congratulations! You’ve made it to the end of SAT Math - Passport to Advanced Math. Good luck studying for the SAT Math section, we believe in you! 👏
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Zaina Siddiqi
Zaina Siddiqi
Welcome to another SAT Math guide! The Passport to Advanced Math portion of the SAT Math exam makes up 16/58 questions, or about 28% of the math section. After mastering this section, you'll be able to analyze more complex equations and solve systems! Let's get started. 🎈
➗ Operations with Polynomials and Rewriting Expressions
Let's begin with operations, which is all about adding, subtracting, and multiplying polynomials.
Skill group number two is all about building quadratic functions! Now let's get into what a quadratic is. 👟
Let's say we have the quadratic expression 3x² - 7x + 2 and we are tasked with finding the solutions (roots) to its corresponding quadratic equation.
Onto group three of skills in this topic! Let's discuss a few vocabulary terms you should be familiar with.
Rational equations often feel tough at first, but once you get in the grove, it gets easier! 🕺🏻🪩
Solve for x in the equation (x + 3)/(2x) = 1/(x - 2).
🤔 Step 1: Identify the domain The expressions have denominators of 2x and (x - 2). To find the domain, set each denominator equal to zero and solve for x:
✖️ Step 2: Cross-multiplication
Multiply the numerator of the first fraction with the denominator of the second fraction, and vice versa: (x + 3)(x - 2) = 2x.
👩🏽💻 Step 3: Simplifying
Expand the left side by distributing: x² - 2x + 3x - 6 = 2x.
Combine like terms: x² + x - 6 = 2x.
💘 Step 4: Solving for the variable
Move all terms to one side to set the equation to zero: x² + x - 2x - 6 = 0.
Simplify further: x² - x - 6 = 0.
🥳 Step 5: Factor the quadratic equation (if possible)
In this case, the equation can be factored as: (x - 3)(x + 2) = 0.
✅ Step 6: Solve for x
Now, use the zero product property, which states that if the product of two factors is zero, then at least one of the factors must be zero:
Since we identified earlier that x cannot be 0 or 2, we need to check the solutions we obtained (x = 3 and x = -2) to ensure they are valid within the domain.
The final solution is x = 3, as x = -2 would make the denominator (x - 2) zero.
Therefore, the solution to the rational equation is x = 3. Phew, that was a lot.
Let's take a simple system of equations with two variables, x and y:
Equation 1: 2x + y = 8
Equation 2: x - y = 2
In this system, we have two equations involving the variables x and y. Our goal is to find the values of x and y that satisfy both equations simultaneously.
Now, let's go through this step by step.
Algebraic Representation: The function is given as f(x) = 2x + 1. This means that for any input value "x," the output "f(x)" is equal to twice the value of "x" plus one. For instance, if we plug in "x = 3," the algebraic representation gives us:
Graphical Representation: To graph this function, we'll plot points on the coordinate plane. Choose several "x" values, find their corresponding "f(x)" values using the algebraic representation, and plot the points (x, f(x)).
Visually, you can see that as the "x" values increase, the "y" values increase twice as fast (due to the coefficient 2) and are always one unit higher (due to the constant term 1). This relationship is evident in both the algebraic and graphical representations. Changes in "x" directly impact the corresponding "y" values, and this connection between the two representations helps us better understand the behavior of functions.
Function notation is a way of representing mathematical relationships between variables. It uses specific symbols to show how one quantity (usually called the input) is related to another quantity (usually called the output). Key concepts in function notation are:
A function notation typically looks like this: f(x). Here, "f" is the name of the function, and "x" represents the input variable. The output of the function when the input is "x" is denoted as f(x).
Now, let's look at an example and explain it step by step: Let's define a function "f" that takes an input "x" and returns the value of 2 times "x" plus 3.
Let's consider a simple example of a function and its graph:
Function: The function represents the relationship between the cost (C) of buying a certain number of tickets (n) to a movie. Let's assume the cost of each ticket is $10.
Equation: The equation for this situation is C = 10 * n. Here, 'n' is the number of tickets purchased, and 'C' is the total cost.
Graph: Now, let's plot the graph of this function. We'll use the x-axis to represent the number of tickets (n) and the y-axis to represent the cost (C).
Graphically, you can see that as the number of tickets increases (n), the cost (C) also increases linearly. Each point on the graph represents a specific input-output pair. For example, if you purchase 2 tickets (n = 2), the total cost would be $20 (C = 10 * 2).
Suppose you want to find out how many tickets you can buy with $50. To do this, we rearrange the equation to solve for 'n': C = 10 * n
Divide both sides by 10: C / 10 = n
Now, plug in C = 50: n = 50 / 10
n = 5
So, you can buy 5 tickets with $50.
This example illustrates how to find connections between the function, its graph, and the situation it represents. It also demonstrates how to rearrange the equation to find the value of interest (number of tickets) given a specific cost.
Congratulations! You’ve made it to the end of SAT Math - Passport to Advanced Math. Good luck studying for the SAT Math section, we believe in you! 👏
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