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4 min readโขjune 18, 2024
Peter Apps
Kashvi Panjolia
Peter Apps
Kashvi Panjolia
Gravitational force describes the interaction of one object with mass with another object with mass.
The gravitational force becomes important only when the masses of the objects are very large, such as planets and stars. The gravitational force is responsible for the orbits of planets and moons, the motion of comets, the formation of galaxies and galaxy clusters, and the behavior of the large-scale structure of the universe.
Equation:ย Fg = mg, where Fg is the force of gravity in Newtons, m is mass in kilograms, and g is the acceleration due to gravity in m/s/s
As you already know, g is the acceleration due to gravity on the Earth's surface, and has a value of 9.8 m/s^2. To calculate g, we can use the equationย g = Fg/m, which is obtained by dividing both sides of the equation above by m.ย
Every particle attracts every other particle in the universe with aย force that isย directly proportional to the product of their masses andย inversely proportional to the square of the distance between their centers. These relationships are modeled by the equation below. This law applies to all objects in the universe and explains the observed gravitational attraction between masses.
Equation:ย Fg = G(m1m2)/r^2, where Fg is the Force of Gravity in Newtons, G is theย gravitational constant (6.7 x 10^-11 Nm^2/kg^2), m is mass in kilograms, and r is the radius in meters.
The gravitational constant is a very small number, which means that the force of gravity between two objects is usually very weak. This is why you are not significantly attracted to the pencil next to you. However, the pencil does have a very weak gravitational force, as does every object in the universe.
Since the product of the two masses in the equation for Newton's Law of Gravitation is in the numerator, we can conclude that an increase in either of the masses (while keeping all other variables constant) will cause an increase in the gravitational force, establishing a directly proportional relationship between the masses and the force. Since r^2, the distance between the two masses, is in the denominator of this equation, we can conclude that an increase in r will result in a decrease in the gravitational force. More specifically, an increase in r will decrease the force by 1/(r^2), creating an inverse-square relationship between the distance between the two masses and the gravitational force.
a) 0.22 N
b) 2.2 N
c) 22 N
d) 220 N
Answer: a) 0.22 Nย
Explanation: F = G(m1*m2)/r^2 = (6.67x10^-11)(10 kg)(*5 kg)/(3^2) = 0.22 N
2. A planet with a mass of 5 x 10^24 kg is located 1.5 x 10^11 meters away from a star with a mass of 2 x 10^30 kg. What is the gravitational force between them?
a) 2.22 x 10^11 N
b) 2.22 x 10^13 N
c) 2.22 x 10^15 N
d) 2.22 x 10^17 N
Answer: d) 2.22 x 10^17 Nย
Explanation: F = G(m1*m2)/r^2 = (6.67x10^-11)(5 x 10^24)(2 x 10^30)/((1.5 x 10^11)^2) = 2.22 x 10^17 N
3. A satellite with a mass of 500 kg is located at a distance of 1000 km from the center of Earth, which has a mass of 5.97 x 10^24 kg. What is the gravitational force acting on the satellite?
a) 1.96 x 10^4 N
b) 3.92 x 10^4 N
c) 7.84 x 10^4 N
d) 1.57 x 10^5 N
Answer: c) 7.84 x 10^4 Nย
Explanation: F = G(m1*m2)/r^2 = (6.67x10^-11)(500)(5.97 x 10^24)/((1000 x 10^3)^2) = 7.84 x 10^4 N
๐ฅWatch: AP Physics 1 -ย Unit 3 Streams
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4 min readโขjune 18, 2024
Peter Apps
Kashvi Panjolia
Peter Apps
Kashvi Panjolia
Gravitational force describes the interaction of one object with mass with another object with mass.
The gravitational force becomes important only when the masses of the objects are very large, such as planets and stars. The gravitational force is responsible for the orbits of planets and moons, the motion of comets, the formation of galaxies and galaxy clusters, and the behavior of the large-scale structure of the universe.
Equation:ย Fg = mg, where Fg is the force of gravity in Newtons, m is mass in kilograms, and g is the acceleration due to gravity in m/s/s
As you already know, g is the acceleration due to gravity on the Earth's surface, and has a value of 9.8 m/s^2. To calculate g, we can use the equationย g = Fg/m, which is obtained by dividing both sides of the equation above by m.ย
Every particle attracts every other particle in the universe with aย force that isย directly proportional to the product of their masses andย inversely proportional to the square of the distance between their centers. These relationships are modeled by the equation below. This law applies to all objects in the universe and explains the observed gravitational attraction between masses.
Equation:ย Fg = G(m1m2)/r^2, where Fg is the Force of Gravity in Newtons, G is theย gravitational constant (6.7 x 10^-11 Nm^2/kg^2), m is mass in kilograms, and r is the radius in meters.
The gravitational constant is a very small number, which means that the force of gravity between two objects is usually very weak. This is why you are not significantly attracted to the pencil next to you. However, the pencil does have a very weak gravitational force, as does every object in the universe.
Since the product of the two masses in the equation for Newton's Law of Gravitation is in the numerator, we can conclude that an increase in either of the masses (while keeping all other variables constant) will cause an increase in the gravitational force, establishing a directly proportional relationship between the masses and the force. Since r^2, the distance between the two masses, is in the denominator of this equation, we can conclude that an increase in r will result in a decrease in the gravitational force. More specifically, an increase in r will decrease the force by 1/(r^2), creating an inverse-square relationship between the distance between the two masses and the gravitational force.
a) 0.22 N
b) 2.2 N
c) 22 N
d) 220 N
Answer: a) 0.22 Nย
Explanation: F = G(m1*m2)/r^2 = (6.67x10^-11)(10 kg)(*5 kg)/(3^2) = 0.22 N
2. A planet with a mass of 5 x 10^24 kg is located 1.5 x 10^11 meters away from a star with a mass of 2 x 10^30 kg. What is the gravitational force between them?
a) 2.22 x 10^11 N
b) 2.22 x 10^13 N
c) 2.22 x 10^15 N
d) 2.22 x 10^17 N
Answer: d) 2.22 x 10^17 Nย
Explanation: F = G(m1*m2)/r^2 = (6.67x10^-11)(5 x 10^24)(2 x 10^30)/((1.5 x 10^11)^2) = 2.22 x 10^17 N
3. A satellite with a mass of 500 kg is located at a distance of 1000 km from the center of Earth, which has a mass of 5.97 x 10^24 kg. What is the gravitational force acting on the satellite?
a) 1.96 x 10^4 N
b) 3.92 x 10^4 N
c) 7.84 x 10^4 N
d) 1.57 x 10^5 N
Answer: c) 7.84 x 10^4 Nย
Explanation: F = G(m1*m2)/r^2 = (6.67x10^-11)(500)(5.97 x 10^24)/((1000 x 10^3)^2) = 7.84 x 10^4 N
๐ฅWatch: AP Physics 1 -ย Unit 3 Streams
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